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Mar 17, 2019 at 21:15 vote accept urquiza
Mar 15, 2019 at 20:46 answer added Ruslan timeline score: 0
Mar 15, 2019 at 20:12 history edited Qmechanic
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Mar 15, 2019 at 20:00 answer added Jahan Claes timeline score: 0
Mar 15, 2019 at 19:14 comment added Jahan Claes Why can't you just say the antisymmetrized version of $\psi$ is your trial wavefunction?
Mar 15, 2019 at 19:05 history edited urquiza CC BY-SA 4.0
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Mar 13, 2019 at 15:15 history asked urquiza CC BY-SA 4.0