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Dec 11, 2012 at 20:11 vote accept JHughes
S Dec 11, 2012 at 11:57 history suggested Claudius CC BY-SA 3.0
no need for c-m tag as we already have h-m, potential is that of newtonian-gravity, removed footer.
Dec 11, 2012 at 11:46 review Suggested edits
S Dec 11, 2012 at 11:57
Dec 11, 2012 at 11:42 answer added juanrga timeline score: 3
Dec 11, 2012 at 5:06 comment added unsym Are you miss the -ve sign in front of the potential? I means $U=-GMm/r^2$ so that $U \to -\infty$. Also, the definition of the total energy $h$ should be $h = T+U$ not $T-U$
Dec 11, 2012 at 1:29 review First posts
Dec 11, 2012 at 2:30
Dec 11, 2012 at 1:10 history asked JHughes CC BY-SA 3.0