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user45664
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Superposition is a result of linearity. If the system is linear then $f(x+y) = f(x)+ f(y)$ which is superposition and which applies to both of your examples.

See https://en.wikipedia.org/wiki/Superposition_principle

"The superposition principle, also known as superposition property, states that, for all linear systems, the net response caused by two or more stimuli is the sum of the responses that would have been caused by each stimulus individually. So that if input A produces response X and input B produces response Y then input (A + B) produces response (X + Y). A function $F(x)$ that satisfies the superposition principle is called a linear function."

Re. '...we say that the interaction between any two charge or mass is independent of presence of other charges or masses' follows from (its a result of) the superposition principle since we can write $f(x+y+z)=f(x)+f(y)+f(z)=f(x+y)+f(z)$ which shows that $f(x+y)$ is not a function of $z$ (the 'other charge or masses'). If $f(z)$ changes it does not effect $f(x+y)$.

So to answer your question: there is only one type of superposition.

Superposition is a result of linearity. If the system is linear then $f(x+y) = f(x)+ f(y)$ which is superposition and which applies to both of your examples.

See https://en.wikipedia.org/wiki/Superposition_principle

"The superposition principle, also known as superposition property, states that, for all linear systems, the net response caused by two or more stimuli is the sum of the responses that would have been caused by each stimulus individually. So that if input A produces response X and input B produces response Y then input (A + B) produces response (X + Y). A function $F(x)$ that satisfies the superposition principle is called a linear function."

Re. '...we say that the interaction between any two charge or mass is independent of presence of other charges or masses' follows from the superposition principle since we can write $f(x+y+z)=f(x)+f(y)+f(z)=f(x+y)+f(z)$ which shows that $f(x+y)$ is not a function of $z$ (the 'other charge or masses').

Superposition is a result of linearity. If the system is linear then $f(x+y) = f(x)+ f(y)$ which is superposition and which applies to both of your examples.

See https://en.wikipedia.org/wiki/Superposition_principle

"The superposition principle, also known as superposition property, states that, for all linear systems, the net response caused by two or more stimuli is the sum of the responses that would have been caused by each stimulus individually. So that if input A produces response X and input B produces response Y then input (A + B) produces response (X + Y). A function $F(x)$ that satisfies the superposition principle is called a linear function."

Re. '...we say that the interaction between any two charge or mass is independent of presence of other charges or masses' follows from (its a result of) the superposition principle since we can write $f(x+y+z)=f(x)+f(y)+f(z)=f(x+y)+f(z)$ which shows that $f(x+y)$ is not a function of $z$ (the 'other charge or masses'). If $f(z)$ changes it does not effect $f(x+y)$.

So to answer your question: there is only one type of superposition.

Source Link
user45664
user45664
  • 3.1k
  • 3
  • 15
  • 34

Superposition is a result of linearity. If the system is linear then $f(x+y) = f(x)+ f(y)$ which is superposition and which applies to both of your examples.

See https://en.wikipedia.org/wiki/Superposition_principle

"The superposition principle, also known as superposition property, states that, for all linear systems, the net response caused by two or more stimuli is the sum of the responses that would have been caused by each stimulus individually. So that if input A produces response X and input B produces response Y then input (A + B) produces response (X + Y). A function $F(x)$ that satisfies the superposition principle is called a linear function."

Re. '...we say that the interaction between any two charge or mass is independent of presence of other charges or masses' follows from the superposition principle since we can write $f(x+y+z)=f(x)+f(y)+f(z)=f(x+y)+f(z)$ which shows that $f(x+y)$ is not a function of $z$ (the 'other charge or masses').