Timeline for Why isn't there any current in the primary if secondary circuit is opened in a transformer?
Current License: CC BY-SA 4.0
11 events
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| Mar 3, 2019 at 4:32 | comment | added | TechDroid | It's all down to the magnetic flux. The alternative magnetic field created has an alternating effect on the electrons in the secondary coil. Adding a resistor in the secondary circuit causes resistance on the electron flow which resonates through the mag field and felt by the electrons in the primary coil creating the field. | |
| Mar 3, 2019 at 2:43 | comment | added | user215726 | One more thing, when a resistor is connected on the secondary, how does the resistor create a 'resistance-like' effect on the primary circuit? | |
| Mar 2, 2019 at 14:02 | comment | added | TechDroid | So that should settle the argument. By this definition, what do you see about your initial comment: "An ideal transformer per definition conserves energy. No secondary load means no power input on the primary coil." So whether ideal or real, the load doesn't determine if there's power input or not. Even in a ideal transformer the primary still induce current into the secondary but it's just in a state of potential until harnessed. | |
| Mar 2, 2019 at 13:26 | comment | added | Jasper | See Wikipedia. Ideal transformer = no energy loss, does not exist. Real transformer = energy losses, draws power even without secondary load. | |
| Mar 2, 2019 at 9:52 | comment | added | TechDroid | If I may ask Jasper, what sets the difference between an ideal transformer and any other transformer | |
| Mar 2, 2019 at 9:50 | comment | added | Jasper | Keep in mind that there is no ideal transformer that you could connect power sources or any "meters" to. | |
| Mar 2, 2019 at 9:02 | history | edited | HolgerFiedler | CC BY-SA 4.0 |
Improved formatting
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| Mar 2, 2019 at 8:34 | comment | added | TechDroid | NO! load means something between the two output terminal, if the primary coil is energized, definitely the secondary is also energized but the current isn't flowing because the secondary circuit isn't close. The secondary winding loaded or unloaded doesn't affect the primary. If you connect the primary of a transformer to an alternating power source and measure the secondary with a meter, you'll definitely get an out if the transformer is well and fine. | |
| Mar 2, 2019 at 8:23 | comment | added | Jasper | An ideal transformer per definition conserves energy. No secondary load means no power input on the primary coil. | |
| Mar 2, 2019 at 6:25 | history | edited | TechDroid | CC BY-SA 4.0 |
More information if needed
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| Mar 2, 2019 at 3:35 | history | answered | TechDroid | CC BY-SA 4.0 |