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i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

below blockquotes is taken from the blog above:

We connect a 1 volt AC generator to a 1 ohm resistor and measure the current. By Ohm’s Law, we should get 1 ampere of current.

 

Now imagine we stuck a 1:10 transformer in the circuit, splitting our one circuit into two electrically-separate circuits. The confusion arises from the following question: does the current through the resistor go up because the voltage went up, or down because the transformer needs to conserve power?

 

Treating the transformer as a 10-volt AC voltage source in the right circuit, we use Ohm’s law to see that the current through the resistor has gone up – it is now 10 amps. In order to preserve power, this means that in the left circuit our original AC power source is now drawing 100 amps of current, 100x what it was drawing before.

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??

i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

below blockquotes is taken from the blog above:

We connect a 1 volt AC generator to a 1 ohm resistor and measure the current. By Ohm’s Law, we should get 1 ampere of current.

Now imagine we stuck a 1:10 transformer in the circuit, splitting our one circuit into two electrically-separate circuits. The confusion arises from the following question: does the current through the resistor go up because the voltage went up, or down because the transformer needs to conserve power?

Treating the transformer as a 10-volt AC voltage source in the right circuit, we use Ohm’s law to see that the current through the resistor has gone up – it is now 10 amps. In order to preserve power, this means that in the left circuit our original AC power source is now drawing 100 amps of current, 100x what it was drawing before.

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??

i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

below blockquotes is taken from the blog above:

we connect a 1 volt AC generator to a 1 ohm resistor and measure the current. By Ohm’s Law, we should get 1 ampere of current.

Now imagine we stuck a 1:10 transformer in the circuit, splitting our one circuit into two electrically-separate circuits. The confusion arises from the following question: does the current through the resistor go up because the voltage went up, or down because the transformer needs to conserve power?

Treating the transformer as a 10-volt AC voltage source in the right circuit, we use Ohm’s law to see that the current through the resistor has gone up – it is now 10 amps. In order to preserve power, this means that in the left circuit our original AC power source is now drawing 100 amps of current, 100x what it was drawing before.

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??

i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

below blockquotes is taken from the blog above:

We connect a 1 volt AC generator to a 1 ohm resistor and measure the current. By Ohm’s Law, we should get 1 ampere of current.

Now imagine we stuck a 1:10 transformer in the circuit, splitting our one circuit into two electrically-separate circuits. The confusion arises from the following question: does the current through the resistor go up because the voltage went up, or down because the transformer needs to conserve power?

Treating the transformer as a 10-volt AC voltage source in the right circuit, we use Ohm’s law to see that the current through the resistor has gone up – it is now 10 amps. In order to preserve power, this means that in the left circuit our original AC power source is now drawing 100 amps of current, 100x what it was drawing before.

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??

i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??

i have read just read this blog:

http://www.blueraja.com/blog/194/do-transformers-obey-ohms-law

below blockquotes is taken from the blog above:

we connect a 1 volt AC generator to a 1 ohm resistor and measure the current. By Ohm’s Law, we should get 1 ampere of current.

Now imagine we stuck a 1:10 transformer in the circuit, splitting our one circuit into two electrically-separate circuits. The confusion arises from the following question: does the current through the resistor go up because the voltage went up, or down because the transformer needs to conserve power?

Treating the transformer as a 10-volt AC voltage source in the right circuit, we use Ohm’s law to see that the current through the resistor has gone up – it is now 10 amps. In order to preserve power, this means that in the left circuit our original AC power source is now drawing 100 amps of current, 100x what it was drawing before.

and, i have something in my textbook stating:

The large scale transmission and distribution of electrical energy over long distances is done with the use of transformers. The voltage output of generator is stepped-up (so that the current is reduced and consequently, the $I^2R$ loss is cut down). It is then transmitted over long distances to an area sub-station near the consumers. There the voltage is stepped-down. It is further stepped-down at the distributing sub-stations and utility pole before a power supply of $240 V$ reaches our homes.

well, as told in the blog, step-up transformers increases both voltage and current proportionally on the secondary side (right side), so $I^2R$ loss increases.. this is confusing me.. have i mistaken something or have a big misconception??

also, why the textbook refers to $I^2R$ loss, why not $VI$ loss or $\frac{V^2}{R}$ loss, which includes voltage, which definitely increases??