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Nov 22, 2017 at 12:48 history edited Qmechanic CC BY-SA 3.0
added 43 characters in body; edited tags; edited title
Jan 4, 2013 at 11:07 history protected Qmechanic
Dec 6, 2012 at 10:02 history tweeted twitter.com/#!/StackPhysics/status/276627616180600832
Dec 5, 2012 at 7:54 history edited Qmechanic CC BY-SA 3.0
space -> spacetime
S Dec 4, 2012 at 23:52 history edited Qmechanic CC BY-SA 3.0
improved title
S Dec 4, 2012 at 23:52 history suggested leongz CC BY-SA 3.0
improved title
Dec 4, 2012 at 23:15 review Suggested edits
Dec 4, 2012 at 23:52
Dec 4, 2012 at 22:42 answer added levitopher timeline score: 1
Dec 4, 2012 at 21:32 comment added Zo the Relativist Yes, but if you're trying to derive the geodesic equation, you lose nothing but headaches by substituting this action with $S = \int ds (g_{ab}{\dot x}^{a}{\dot x}^{b})$, where ${\dot x}^{a} = \frac{\partial x^{a}}{\partial s}$, since a minimum of $\int f(x)$ is also going to be a minimum of $\int (f(x))^{2}$
S Dec 4, 2012 at 21:09 history edited Qmechanic
-Mc was missed, added
S Dec 4, 2012 at 21:09 history suggested CommunityBot CC BY-SA 3.0
-Mc was missed, added
Dec 4, 2012 at 20:43 review Suggested edits
Dec 4, 2012 at 21:09
Dec 4, 2012 at 20:01 answer added Prathyush timeline score: 1
S Dec 4, 2012 at 19:57 history edited CommunityBot
remove duplicate link
S Dec 4, 2012 at 19:57 history reopened dmckee --- ex-moderator kitten
S Dec 4, 2012 at 19:55 history edited CommunityBot
insert duplicate link
S Dec 4, 2012 at 19:55 history closed dmckee --- ex-moderator kitten exact duplicate
Dec 4, 2012 at 19:30 history asked Neo CC BY-SA 3.0