Timeline for How does the complexity in Matrix Product states ansatz drop from $D^N$ to $ND$?
Current License: CC BY-SA 4.0
12 events
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Mar 24, 2022 at 13:37 | vote | accept | Fracton | ||
Jan 12, 2022 at 6:18 | comment | added | Jordan Taylor | My answer to this related question may be useful: physics.stackexchange.com/questions/688211/… | |
Jan 11, 2022 at 21:00 | history | tweeted | twitter.com/StackPhysics/status/1481008040384028678 | ||
Jan 10, 2022 at 13:02 | answer | added | TA-25 | timeline score: 3 | |
Jun 4, 2020 at 16:03 | history | edited | CommunityBot |
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Feb 10, 2019 at 15:57 | comment | added | Fracton | I really want to understand what is the advantage of talking about t-DMRG in terms of MPS ansatz rather than traditional terms in which it was first formulated. | |
Feb 10, 2019 at 15:52 | comment | added | Fracton | I don't get it, I find that MPS is a way to reorganize and rewrite the coefficients. Please correct me if I am wrong about this. | |
Feb 1, 2019 at 15:09 | comment | added | Sunyam | Using singular value decomposition on wave function expansion coefficients, you can proove MPS representation for arbitrary many body wave function. In this step, if I am correct you dont reduce any complexity. I think you further need to assume/approximate some value bond dimensions. If you impose bond dimensions to be unity i. e., matrices of MPS are scalars, then you will have simple standard mean field ansatz. | |
Feb 1, 2019 at 13:12 | comment | added | Fracton | I want to understand the of how the complexity for $ C^i's $ scales down and what really is the basis for MPS and how does link up to mean field theory. | |
Feb 1, 2019 at 13:10 | history | edited | Fracton | CC BY-SA 4.0 |
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Feb 1, 2019 at 9:40 | comment | added | Norbert Schuch | Can you add some details about what you want to understand? Otherwise "it has less parameters" seems a valid answer. | |
Feb 1, 2019 at 8:37 | history | asked | Fracton | CC BY-SA 4.0 |