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Mar 24, 2022 at 13:37 vote accept Fracton
Jan 12, 2022 at 6:18 comment added Jordan Taylor My answer to this related question may be useful: physics.stackexchange.com/questions/688211/…
Jan 11, 2022 at 21:00 history tweeted twitter.com/StackPhysics/status/1481008040384028678
Jan 10, 2022 at 13:02 answer added TA-25 timeline score: 3
Jun 4, 2020 at 16:03 history edited CommunityBot
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Feb 10, 2019 at 15:57 comment added Fracton I really want to understand what is the advantage of talking about t-DMRG in terms of MPS ansatz rather than traditional terms in which it was first formulated.
Feb 10, 2019 at 15:52 comment added Fracton I don't get it, I find that MPS is a way to reorganize and rewrite the coefficients. Please correct me if I am wrong about this.
Feb 1, 2019 at 15:09 comment added Sunyam Using singular value decomposition on wave function expansion coefficients, you can proove MPS representation for arbitrary many body wave function. In this step, if I am correct you dont reduce any complexity. I think you further need to assume/approximate some value bond dimensions. If you impose bond dimensions to be unity i. e., matrices of MPS are scalars, then you will have simple standard mean field ansatz.
Feb 1, 2019 at 13:12 comment added Fracton I want to understand the of how the complexity for $ C^i's $ scales down and what really is the basis for MPS and how does link up to mean field theory.
Feb 1, 2019 at 13:10 history edited Fracton CC BY-SA 4.0
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Feb 1, 2019 at 9:40 comment added Norbert Schuch Can you add some details about what you want to understand? Otherwise "it has less parameters" seems a valid answer.
Feb 1, 2019 at 8:37 history asked Fracton CC BY-SA 4.0