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Nov 3 at 13:10 comment added Qmechanic Notes for later: \begin{align} t(\theta) ~=~& e^{-i\theta} t_E, \qquad \theta~\in~[0,\frac{\pi}{2}], \cr t(\theta\!=\!0)~=~&t_E, \qquad t(\theta\!=\!\frac{\pi}{2})~=~-it_E=t_M. \end{align}
Sep 25 at 7:34 comment added Qmechanic Notes to self: Hm. There still seems to be room for a sign ambiguity in interpretation, cf. physics.stackexchange.com/q/828807/2451
Oct 2, 2022 at 8:37 history edited Qmechanic CC BY-SA 4.0
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Jan 31, 2019 at 23:39 vote accept P. C. Spaniel
Jan 31, 2019 at 21:52 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jan 30, 2019 at 18:44 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jan 30, 2019 at 18:13 history edited Qmechanic CC BY-SA 4.0
Added explanation
Jan 30, 2019 at 17:55 history answered Qmechanic CC BY-SA 4.0