Timeline for Physical Interpretation of $\nabla \cdot \vec{E} = \frac{\rho}{\epsilon_0} $
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| Nov 17, 2019 at 11:00 | comment | added | Maan | The answer to the question in given link may be helpful too physics.stackexchange.com/q/510416/227794 | |
| Nov 17, 2019 at 9:38 | history | edited | Qmechanic♦ |
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| Jan 27, 2019 at 15:22 | vote | accept | TaeNyFan | ||
| Jan 23, 2019 at 22:37 | comment | added | Voulkos | Related : Divergence of Electric Field Due to a Point Charge | |
| Jan 23, 2019 at 21:15 | answer | added | Zecheng Gan | timeline score: 1 | |
| Jan 23, 2019 at 19:20 | comment | added | G. Smith | Oh, of course. Sorry about that, FGSUZ. | |
| Jan 23, 2019 at 19:18 | comment | added | BioPhysicist | @G.Smith I think FGSUZ is talking about the Coulomb's law equation | |
| Jan 23, 2019 at 19:14 | comment | added | G. Smith | @FGSUZ The divergence of a vector is a scalar. There should be a vector sign over the $\nabla$ for clarity, but not a unit vector on the right hand side. | |
| Jan 23, 2019 at 19:12 | answer | added | Trevor Kafka | timeline score: 2 | |
| Jan 23, 2019 at 19:12 | comment | added | FGSUZ | 2 things. 1) Field and divergence of a field are not the same. 2) The electric field is not defined on the charge itself. You forget that vector = vector. Where is the vector in your RHS? You missed a unit vector $\hat{r}$. Where does it point to? It's undefined | |
| Jan 23, 2019 at 19:11 | comment | added | G. Smith | Just calculate the divergence of the Coulomb field you wrote and you will see that it is zero everywhere except at $r=0$. | |
| Jan 23, 2019 at 19:05 | answer | added | BioPhysicist | timeline score: 3 | |
| Jan 23, 2019 at 19:01 | history | asked | TaeNyFan | CC BY-SA 4.0 |