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Jan 17, 2019 at 2:17 comment added Marcus Thanks @user1476176. I omitted the surrounding temperature dependence of the heat loss rate to simplify my question. Your second point about the temperature gradient inside the black body can also be ignored in my case as I'm dealing with tiny particles of a very good conductor. Thanks for the input though.
Jan 15, 2019 at 10:05 history answered user1476176 CC BY-SA 4.0