Timeline for Why doesn’t current decrease when it passes through a resistor?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 13, 2019 at 7:42 | comment | added | Karthik | @NagaSandeshGoli even the time component will increase, along with the number density. If you use the current density formula ($j$), you can see the relation. | |
| Jan 13, 2019 at 7:37 | comment | added | Sandesh Goli | n=free electron density. Free electron density is high in resistor (since it is conductor). | |
| Jan 13, 2019 at 7:35 | comment | added | Chemist | So you are saying the decrease in speed is compensated by increase in number of electrons ... but how did they suddenly appear there | |
| Jan 13, 2019 at 7:33 | comment | added | Sandesh Goli | We know that i=neav (v=drift velocity). In resistor 'v' decreases, 'n' increases. All the variables adjust themselves. | |
| Jan 13, 2019 at 7:31 | comment | added | Chemist | I agree that the charge does not stay there but it moves slowly | |
| Jan 13, 2019 at 7:30 | comment | added | Sandesh Goli | If we are able to store the charge continuously then current is not same on both sides. | |
| Jan 13, 2019 at 7:29 | comment | added | Chemist | I have mentioned the same , the charge does not stay there but it moves slowly due to restriction by resistor. Causing time component to increase | |
| Jan 13, 2019 at 7:26 | history | answered | Sandesh Goli | CC BY-SA 4.0 |