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Is the Palatini-Lovelock action of order k$k$ topological in 2k$2k$ dimensions?

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Gravitino
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I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?


If it were true:

What does it mean to be "topological" in this particular context? [See https://physics.stackexchange.com/questions/262660/two-definitions-of-topological-terms-in-field-theory ] The metric theory can be written as a total derivative; but I think there is no way to do so in the metric-affine case (expanding the connection 2-form using the Cartan's structure equation and trying to extract one of the exterior derivatives), so it must be topological in the other sense. I am confused.

I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?


If it were true:

What does it mean to be "topological" in this particular context? [See https://physics.stackexchange.com/questions/262660/two-definitions-of-topological-terms-in-field-theory ] The metric theory can be written as a total derivative; but I think there is no way to do so in the metric-affine (expanding the connection 2-form using the Cartan's structure equation and trying to extract one of the exterior derivatives), so it must be topological in the other sense. I am confused.

I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?


If it were true:

What does it mean to be "topological" in this particular context? [See https://physics.stackexchange.com/questions/262660/two-definitions-of-topological-terms-in-field-theory ] The metric theory can be written as a total derivative; but I think there is no way to do so in the metric-affine case (expanding the connection 2-form using the Cartan's structure equation and trying to extract one of the exterior derivatives), so it must be topological in the other sense. I am confused.

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Gravitino
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I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?


If it were true:

What does it mean to be "topological" in this particular context? [See https://physics.stackexchange.com/questions/262660/two-definitions-of-topological-terms-in-field-theory ] The metric theory can be written as a total derivative; but I think there is no way to do so in the metric-affine (expanding the connection 2-form using the Cartan's structure equation and trying to extract one of the exterior derivatives), so it must be topological in the other sense. I am confused.

I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?

I am interested in Lovelock actions in the metric-affine (or Palatini) formalism. It is well-known that the metric version (starting from the Levi-Civita curvature) of the Lovelock lagrangian of order $k$ is a topological term in $2k$ dimensions. For example, the case $k=2$ is the Gauss-Bonnet term.

I have also read in texts on Poincaré gauge gravity (now the connection contains torsion but not non-metricity) that this is also true for torsionful-Lovelock actions.

But some people extrapolate this to the general metric-affine-Lovelock action (with torsion and non-metricity, i.e. a completely general affine connection), but I cannot find the proof anywhere.

Is this true in general? Is it easy to prove?


If it were true:

What does it mean to be "topological" in this particular context? [See https://physics.stackexchange.com/questions/262660/two-definitions-of-topological-terms-in-field-theory ] The metric theory can be written as a total derivative; but I think there is no way to do so in the metric-affine (expanding the connection 2-form using the Cartan's structure equation and trying to extract one of the exterior derivatives), so it must be topological in the other sense. I am confused.

res. recom can usually not be mixed with an actual phys. q
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