Timeline for Are any quantum field theories mathematically convergent?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Dec 28, 2018 at 1:37 | comment | added | user84158 | @Dan In my view not having a continuum limit means the theory is not well defined because only in the limit are all symmetries manifest. We may differ on terminology. "Probably" is not really mathematically rigorous! I'm not concerned with physical reality, just if the mathematics is well defined. | |
| Dec 27, 2018 at 17:27 | comment | added | user84158 | @Dan Just if QED are well defined on the lattice really. | |
| S Dec 25, 2018 at 16:43 | history | suggested | David Schaich |
Add a lattice tag
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| Dec 25, 2018 at 16:22 | review | Suggested edits | |||
| S Dec 25, 2018 at 16:43 | |||||
| Dec 25, 2018 at 16:17 | answer | added | David Schaich | timeline score: 4 | |
| Dec 25, 2018 at 15:25 | comment | added | user84158 | @InitialObserver nope, not closed form, just convergent and non-asymptotic methods of getting precise values. | |
| Dec 25, 2018 at 15:22 | comment | added | user84158 | @Dan Yard. well-defined series that are not convergent are not well defined. As in it can only give an approximation to a certain number of decimal places before the series diverges again. I'm not sure what you mean by "well-defined but non-convergent". Do you mean there is another way to get the values that does converge to a single value? Do you mean the lattice theory gives precise answers but the perturbation method doesn't? | |
| Dec 25, 2018 at 3:42 | comment | added | InertialObserver | I think OP may also be asking about the existence of "closed" form solutions to the equations of motion in QFTs | |
| Dec 25, 2018 at 1:15 | history | asked | user84158 | CC BY-SA 4.0 |