Timeline for If centrifugal force is fictitious, what force is real in its stead?
Current License: CC BY-SA 4.0
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| Dec 13, 2018 at 17:42 | history | edited | Ben51 | CC BY-SA 4.0 |
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| Dec 12, 2018 at 17:35 | history | edited | Ben51 | CC BY-SA 4.0 |
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| Dec 12, 2018 at 0:09 | comment | added | A.V. Arno | ,the statement that there is no force that overcomes friction doesn't seem to fit with the statement that "force must be applied to overcome the static force of friction before an object can be moved". If i want to move a table, I push it with force to overcome the force of friction. Similarly, to move the car against static lateral force of friction to the outside of the turn, some force must push it out, no? I mean, what you explain makes intuitive sense, but I just don't understand how it fits with the explanation of static friction, third law of newton about opposite forces etc. | |
| Dec 11, 2018 at 23:53 | comment | added | Ben51 | In the inertial frame, that is not a correct description of the situation. There is NO force which "overcomes" friction. There is only one force on the car: friction. That's why it goes in a curve instead of straight. When the driver asks the car to turn so sharply that friction can no longer provide the needed force, the wheels start to slide. | |
| Dec 11, 2018 at 23:51 | comment | added | A.V. Arno | I mean, the moment when car breaks into sliding, the force of friction becomes exceeded by the force that opposes it - hence it can't hold the car on track anymore. But what is that force that acts against the force of friction and breaks it if the turn is too steep? There should be a force that acts against the force of friction, right? | |
| Dec 11, 2018 at 23:50 | comment | added | Ben51 | Sounds like you're not so confused. | |
| Dec 11, 2018 at 23:49 | comment | added | A.V. Arno | now I'm even more confused. Centripetal force pulls car into turning (apparently, centripetal in this case being the force of friction, because it prevents car from continuing going forward and thus makes it turn). But what force acts opposite to it? | |
| Dec 11, 2018 at 23:44 | comment | added | Ben51 | You can call it "centripetal force". It's the force required to make something change its direction of motion. In this case it's provided by friction between the road and the tires. For a stone whirling around on a string, it's the tension in the string. etc etc | |
| Dec 11, 2018 at 23:43 | comment | added | A.V. Arno | "lateral force" So, is this the term for it? Because google shows this term only as a characteristic of tires, not as a physical force. | |
| Dec 11, 2018 at 23:34 | history | answered | Ben51 | CC BY-SA 4.0 |