Timeline for Are the Maxwell's equations enough to derive the law of Coulomb?
Current License: CC BY-SA 4.0
17 events
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Oct 18, 2018 at 8:59 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
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Jan 16, 2014 at 1:23 | answer | added | wonderich | timeline score: 10 | |
Jan 15, 2014 at 22:42 | history | protected | Qmechanic♦ | ||
Jan 15, 2014 at 22:26 | answer | added | Srr | timeline score: 1 | |
Jun 25, 2013 at 14:15 | answer | added | Janek_Kozicki | timeline score: 12 | |
Nov 17, 2012 at 13:38 | answer | added | Emilio Pisanty | timeline score: 19 | |
Nov 17, 2012 at 13:01 | history | tweeted | twitter.com/#!/StackPhysics/status/269787558727266305 | ||
Nov 17, 2012 at 13:01 | comment | added | Dani | Spherical symmetry is not incorporated in Maxwell's equation. To go from Gauss' law to Coulomb's law for point-like particles which produces a spherical symmetric electric field in the space this assumption has to be made. In addition, Maxwell's equations do not tell you that there is no magnetic field, they just tell you that there are no magnetic monopoles (Gauss' law again). Electric and magnetic fields are two sides of the same field: electromagnetic field. | |
Nov 17, 2012 at 12:52 | comment | added | achatrch | @Daniel Blay: I guess when you say usual tricks you mean taking a spherical surface around the point charge. The problem for me is that how do we know that the magnitude of the electric field from a point charge is spherically-symmetric. Besides how can we derive that there is no magnetic field (if it is possible to derive from Maxwell's equations)? :) | |
Nov 17, 2012 at 12:45 | comment | added | achatrch | @DanilH: I meant 8 scalar equations. From the 4 Maxwell's equations two are vector equations. | |
Nov 17, 2012 at 12:35 | comment | added | Dani | Why 8 Maxwell's equations and not 4? I am missing something? | |
Nov 17, 2012 at 12:31 | comment | added | Daniel Blay | Wouldn't it be trivial to apply the divergence theorem to Gauss' law to get it in its integral form. From here it seems easy enough to use the usual tricks to find the electric field of a point charge, and then multiply by some charge to get your force. Surely this is Coulomb's force law? | |
Nov 17, 2012 at 11:54 | comment | added | achatrch | Yes, I have already read this post, but my question is quite different. | |
Nov 17, 2012 at 11:28 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Nov 17, 2012 at 11:27 | comment | added | Qmechanic♦ | For essentially the opposite question(v3), see this Phys.SE post. | |
Nov 17, 2012 at 11:25 | history | edited | Waffle's Crazy Peanut | CC BY-SA 3.0 |
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Nov 17, 2012 at 11:19 | history | asked | achatrch | CC BY-SA 3.0 |