Timeline for What kind of ideal gas process a positively sloped line in a $pV$-diagram represents?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Nov 29, 2018 at 17:38 | comment | added | Farcher | @Drew The equation of the straight line in this case is $P = bV + a$, compare with the general equation of a straight line $y=mx+c$, and the equation of state is $PV=nRT$ | |
| Nov 29, 2018 at 16:13 | comment | added | user65081 | @Drew yes, just as Chester Miller said | |
| Nov 29, 2018 at 16:11 | comment | added | Chet Miller | @Drew All he is saying is that the temperature is rising in a specific way along the process path. From the ideal gas law, T=PV/nR, so for any combination of P and V along the process path, you can calculate a corresponding temperature. | |
| Nov 29, 2018 at 15:55 | comment | added | Thermodynamix | "In order to do that you need to put the gas in contact with a variable thermal source whose temperature will augment quadratically with the volume: $T=(a+bV)V/nR$" Why? This is not obvious to me. | |
| Nov 29, 2018 at 15:51 | history | answered | user65081 | CC BY-SA 4.0 |