Timeline for Convert magnetic field from cylindrical to cartesian coordinates
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Nov 24, 2018 at 17:30 | history | edited | Daddy Kropotkin | CC BY-SA 4.0 |
cartesian unit vectors needed the hat instead of the arrow
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| Nov 24, 2018 at 14:33 | vote | accept | freja | ||
| Nov 24, 2018 at 14:32 | history | edited | Daddy Kropotkin | CC BY-SA 4.0 |
added 275 characters in body
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| Nov 24, 2018 at 14:10 | comment | added | freja | Thank you - is there a way to remove sin, cos, tan completely? My aim is to get to the final equation in the question, but I'm stumbling at the end. | |
| Nov 24, 2018 at 13:39 | history | edited | Daddy Kropotkin | CC BY-SA 4.0 |
added 266 characters in body
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| Nov 24, 2018 at 13:33 | comment | added | Daddy Kropotkin | I just made an edit, so re-examine the answer please. But, you asked how to convert the cylindrical unit vector into a linear combination of cartesian unit vectors, and that's what is provided, so if you substitute the expression for $\hat{e}_{\phi}$ in terms of the cartesian unit vectors then your magnetic field will then be in terms of the cartesian unit vectors, and if you want to remove the explicit $\phi$ dependence then you use the coordinate transformations to sub in for $x$ and $y$. Does that make sense? | |
| Nov 24, 2018 at 13:31 | history | edited | Daddy Kropotkin | CC BY-SA 4.0 |
added 207 characters in body
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| Nov 24, 2018 at 13:30 | comment | added | freja | Thank you, but how does this lead to the equation in x and y unit vectors without sin and cos? | |
| Nov 24, 2018 at 13:26 | history | answered | Daddy Kropotkin | CC BY-SA 4.0 |