Timeline for How to tie in black body radiation with quantum theory?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 22, 2018 at 17:15 | comment | added | Gonstasp | Thermal radiation occurs when the internal energy of atoms or molecules is converted into electromagnetic energy, this happens thanks to the motion of charged particles (protons and electrons present in your black body). As you know dipole oscillations produce electromagnetic waves. I am not sure what to answer to your first question, the path of the photon would simply be a straight line once it is emitted. I suggest you ask a new question so you can gather more answer about this specific problem. | |
| Nov 22, 2018 at 17:02 | comment | added | gerry | If one were to trace the path of a photon emitted from a blackbody, from its beginning, what would it look like? Does the internal energy of the object cause the electrons to excite and relax, emitting the photons? Is it some other process? I'm trying to better tie down these graphs with what is occurring microscopically. | |
| Nov 22, 2018 at 16:53 | comment | added | Gonstasp | UV photons are indeed local oscillations of the electromagnetic field that propagates in space, just like optical photons. This holds even at higher frequencies, for X photons or gamma photons. There is no difference, only the frequency and thus the energy $E=h\nu$ carried by the photon vary. | |
| Nov 22, 2018 at 16:49 | comment | added | gerry | Is the emission the product of electronic oscillations? Presumably at the higher frequencies it is some other source? | |
| Nov 22, 2018 at 15:21 | history | edited | Gonstasp | CC BY-SA 4.0 |
Trying to be more clear
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| Nov 22, 2018 at 14:53 | history | answered | Gonstasp | CC BY-SA 4.0 |