Timeline for How to get the four-velocity components from a given metric tensor?
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Jun 29, 2021 at 14:10 | history | edited | Qmechanic♦ |
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Jun 29, 2021 at 14:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Feb 24, 2021 at 11:07 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Aug 1, 2020 at 15:15 | answer | added | Jacopo Tissino | timeline score: 2 | |
Aug 1, 2020 at 15:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
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Jul 24, 2019 at 18:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Mar 25, 2019 at 15:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Nov 11, 2018 at 11:33 | answer | added | kalle | timeline score: 0 | |
Nov 11, 2018 at 11:03 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
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Nov 11, 2018 at 10:51 | comment | added | m4r35n357 | This is because the metric does not contain any information about four-velocity! The only "connection" that I am aware of, is using the derivatives of the metric (Christoffel symbols), each multiplied by two four-vectors, to calculate geodesic motion. en.wikipedia.org/wiki/Geodesics_in_general_relativity | |
Nov 11, 2018 at 10:26 | history | asked | Joan Carles Soliva | CC BY-SA 4.0 |