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Nov 21, 2018 at 16:52 comment added Nicolas @Ajay Yes, that's correct.
Nov 21, 2018 at 11:40 comment added Ajay Thanks@Nicolas. So, this is what I understood. Electric field is already present in the battery and this electric field pulled the electrons from plate of the capacitior. Did I understand correctly?
Nov 21, 2018 at 10:11 comment added Nicolas The electric field is immediately present across the battery ; the internal resistance of the battery (and that of your wires) limits the current that is pushed by this electric field and therefore the speed at which it appears across the capacitor plates. In other words, the current propagates "slowly" along the wire to the capacitor due to the resistive slowing of moving electrons in the wire/battery.
Nov 20, 2018 at 15:34 comment added Ajay Hi @Nicolas, This may be a dumb question, When we connect the positive and negative of a cell to capacitor, electric field is formed inside capacitor only after some electrons are transferred from plate of the capacitor to positive terminal of the cell,aren't it? So how this transfer of electrons takes place first without an electric field being already present?
Nov 20, 2018 at 15:23 vote accept Ajay
Nov 7, 2018 at 16:46 history answered Nicolas CC BY-SA 4.0