Timeline for Will $Q_1 - Q_2$ be valid for a steady flow open system exchanging heat with two thermal energy reservoirs?
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 11, 2018 at 18:14 | comment | added | Chet Miller | What does the open system (control volume) version of the first law tell you about this situation (assuming steady state operation)? Can you write down the equation please? (Of course, this is not a cycle) | |
| Nov 11, 2018 at 17:33 | comment | added | Gaurav Kumar Barik | Sir what if the working fluid exiting from last control volume of the system is discharged out of the system and new working fluid( same in quantity as much discharged) enters the system for next cycle, then is the formula Q1 - Q2 is applicable to find net work output? | |
| Nov 5, 2018 at 17:19 | answer | added | Bob D | timeline score: 0 | |
| Nov 4, 2018 at 17:27 | comment | added | Chet Miller | If there are several devices operating at steady state within a combined system in which the flow out of one device is equal to the flow into the next device and so forth, and, if there is no flow into or out of the combined combination of devices, the overall combined system of devices is a closed system. Each individual device within the sequence is an open system. | |
| Nov 4, 2018 at 17:22 | comment | added | Gaurav Kumar Barik | Sir, if mass flows in and out in a steady flow system then it is an open system but works in a cycle. So for this system can we conclude that work produced is Q1 - Q2? | |
| Nov 4, 2018 at 17:19 | comment | added | Chet Miller | I never heard of the term "open cycle." | |
| Nov 4, 2018 at 17:18 | comment | added | Gaurav Kumar Barik | Aren't an open system with steady flow and open cycle the same? | |
| Nov 4, 2018 at 17:18 | comment | added | Chet Miller | Well, for each of the devices in a cyclic power system like a Rankine cycle (e.g., the turbine), the device itself can be regarded as an open system, with working fluid flowing in and out at steady state. The entire cyclic system can be regarded as closed, but with different open system processes taking place simultaneously within the overall system. | |
| Nov 4, 2018 at 17:10 | comment | added | Gaurav Kumar Barik | But if it is an open system with steady flow? | |
| Nov 4, 2018 at 16:47 | comment | added | Chet Miller | Sure, as long as it is a closed cycle. | |
| Nov 4, 2018 at 14:56 | comment | added | Gaurav Kumar Barik | LET there be closed system in which their is a fixed mass working fluid and system Taking heat Q1 from Reservoir at T1 and rejecting Q2 at T2. And then there be another system which is of steady flow type open system operating in a cycle exchanging heat Q1 & Q2 between the two reservoirs at T1 & T2 respectively . Is the the work produced by steady flow system is equal to Q1 - Q2. | |
| Nov 4, 2018 at 14:50 | comment | added | Gaurav Kumar Barik | No sir. I am referring to a general steady flow open system. | |
| Nov 4, 2018 at 12:27 | comment | added | Chet Miller | Can you please provide a specific example that we can focus on? Are you referring, perhaps, to a Rankine power cycle? | |
| Nov 4, 2018 at 7:34 | history | edited | Nat | CC BY-SA 4.0 |
added 45 characters in body; edited title
|
| Nov 4, 2018 at 7:04 | history | asked | Gaurav Kumar Barik | CC BY-SA 4.0 |