An electron with an initial speed of $4.0 × 10^ 6 m/s$ is brought to rest by an electric field. The mass and charge of an electron are $9 × 10 ^{-31} kg$ and $1.6 × 10 ^{19}C$, respectively. Identify the correct statement

(A) The electron moves from a region of lower potential to higher potential through a potential difference of 11.4 V.

(B) The electron moves from a region of higher potential to lower potential through a potential difference of 11.4 V.

(C) The electron moves from a region of lower potential to higher potential through a potential difference of 45 V.

(D) The electron moves from a region of higher potential to lower potential through a potential difference of 45 V

My approach: $Q*V = 1/2 * m * v^2$(wor done by electric field is used to bring electron to rest)

So $ V = \dfrac{(1/2 * 9 * 10^{-31} * (4*10^6)^2)}{1.6 * 10^{-19}} = 45$ volts

Now, my doubt is in option C and D. I thought that it would be option C as an electron always moves from a lower to higher potential. But the answer is given as option D.