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Oct 24, 2018 at 13:21 vote accept Dimitri
Oct 24, 2018 at 13:21 comment added Dimitri @MichaelSeifert You are right, I should have added the depletion term to $\partial{\rho}/\partial{t}$, i.e. $\partial{\rho}/\partial{t} = D\nabla^2 \rho - k \rho$ at $x=0$
Oct 24, 2018 at 12:57 comment added Michael Seifert Also, see this old answer of mine for a cautionary tale on setting a "boundary at $r = 0$" in cylindrical coordinates. The same argument would apply to a spherical coordinate system.
Oct 24, 2018 at 12:53 comment added Michael Seifert In eq (1), the right-hand side would be $D \nabla^2 \rho + k \nabla \cdot \rho$ at $x = 0$. Naïvely, this looks like you're adding a scalar to a vector. Can you clarify what you mean by editing the question?
Oct 24, 2018 at 12:08 answer added Chet Miller timeline score: 2
Oct 24, 2018 at 6:17 comment added Deep Look at this.
Oct 24, 2018 at 2:05 review Close votes
Nov 11, 2018 at 19:18
Oct 24, 2018 at 1:13 history edited Dimitri CC BY-SA 4.0
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Oct 23, 2018 at 23:24 history edited Dimitri CC BY-SA 4.0
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Oct 23, 2018 at 23:10 review First posts
Oct 24, 2018 at 0:43
Oct 23, 2018 at 23:06 history asked Dimitri CC BY-SA 4.0