Timeline for What is the meaning of $PV^\gamma=$ constant in an adiabatic process?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Oct 19, 2018 at 19:40 | comment | added | Žarko Tomičić | I used isothermal because I dont know how to write exponents here :-) | |
| Oct 19, 2018 at 19:38 | comment | added | Bøbby Leung | Oh right sorry I mixed up your isothermal explanation with the adiabatic process. But I think I'm starting to know where my misunderstanding is, thanks for explaining. | |
| Oct 19, 2018 at 19:20 | comment | added | Žarko Tomičić | System can change its internal energy U through basicaly two processes: doing work and exchange of heat. However, temperature is not the same as heat. Isothermal means for example, if you do the work on the system, you give it enough time to adjust and dissipate heat so it would be a slow process. In this process, you disipate heat just to stay on the same temperature. Also, if the system does the work, then it is given enough time to absorb heat to stay on the same temperature. So, system stays on the same temp and dU is zero, but dW and dQ are not, they are actually the same: dW + dQ = 0 | |
| Oct 19, 2018 at 18:46 | comment | added | Bøbby Leung | Thanks for the input. But if P and V changes in the isotermic process, then that'd imply work is done on the system/surrounding? And thus ΔU is non-zero? And thus temperature isn't constant? | |
| Oct 19, 2018 at 18:32 | history | answered | Žarko Tomičić | CC BY-SA 4.0 |