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Added comments explaining why this answer is distinct from giving an approximation of acceleration.
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The difference between an approximation of acceleration and an exact formulation of average acceleration can be seen by observing that thee data points are sufficient to approximate instantaneous acceleration; a formulation of average acceleration requires a minimum of four data points.

That I have provided distinct expressions for these distinct quantities should be sufficient to convince the qualified reader of the distinction between these similar concepts.

The answer is: Yes, it is possible to formulate an exact expression which can reasonably be called average acceleration. What I have called the approximate acceleration at time $t_p$ is an exactly defined value derived from two average velocities. Applying the same method to two consecutive "approximate" accelerations gives the two forms

$$\left\langle \mathfrak{a}_{p}\right\rangle \equiv\frac{\mathfrak{a}_{p}-\mathfrak{a}_{p-1}}{\Delta t}$$

$$=\frac{1}{\Delta t^{2}}\left(\left\langle \mathfrak{v}_{p+1}\right\rangle -2\left\langle \mathfrak{v}_{p}\right\rangle +\left\langle \mathfrak{v}_{p-1}\right\rangle \right)$$

$$=\frac{1}{\Delta t^{3}}\left(\mathfrak{r}_{p+1}+3\left(\mathfrak{r}_{p-1}-\mathfrak{r}_{p}\right)-\mathfrak{r}_{p-2}\right).$$

I'm not convinced of the utility of this expression, but it is an exact formulation consisting entirely of the input data, having a form similar to that used for average velocity.

I strongly urge anyone wishing to borrow this result to double-check my algebra and reasoning.

The answer is: Yes, it is possible to formulate an exact expression which can reasonably be called average acceleration. What I have called the approximate acceleration at time $t_p$ is an exactly defined value derived from two average velocities. Applying the same method to two consecutive "approximate" accelerations gives the two forms

$$\left\langle \mathfrak{a}_{p}\right\rangle \equiv\frac{\mathfrak{a}_{p}-\mathfrak{a}_{p-1}}{\Delta t}$$

$$=\frac{1}{\Delta t^{2}}\left(\left\langle \mathfrak{v}_{p+1}\right\rangle -2\left\langle \mathfrak{v}_{p}\right\rangle +\left\langle \mathfrak{v}_{p-1}\right\rangle \right)$$

$$=\frac{1}{\Delta t^{3}}\left(\mathfrak{r}_{p+1}+3\left(\mathfrak{r}_{p-1}-\mathfrak{r}_{p}\right)-\mathfrak{r}_{p-2}\right).$$

I'm not convinced of the utility of this expression, but it is an exact formulation consisting entirely of the input data, having a form similar to that used for average velocity.

I strongly urge anyone wishing to borrow this result to double-check my algebra and reasoning.

The difference between an approximation of acceleration and an exact formulation of average acceleration can be seen by observing that thee data points are sufficient to approximate instantaneous acceleration; a formulation of average acceleration requires a minimum of four data points.

That I have provided distinct expressions for these distinct quantities should be sufficient to convince the qualified reader of the distinction between these similar concepts.

The answer is: Yes, it is possible to formulate an exact expression which can reasonably be called average acceleration. What I have called the approximate acceleration at time $t_p$ is an exactly defined value derived from two average velocities. Applying the same method to two consecutive "approximate" accelerations gives the two forms

$$\left\langle \mathfrak{a}_{p}\right\rangle \equiv\frac{\mathfrak{a}_{p}-\mathfrak{a}_{p-1}}{\Delta t}$$

$$=\frac{1}{\Delta t^{2}}\left(\left\langle \mathfrak{v}_{p+1}\right\rangle -2\left\langle \mathfrak{v}_{p}\right\rangle +\left\langle \mathfrak{v}_{p-1}\right\rangle \right)$$

$$=\frac{1}{\Delta t^{3}}\left(\mathfrak{r}_{p+1}+3\left(\mathfrak{r}_{p-1}-\mathfrak{r}_{p}\right)-\mathfrak{r}_{p-2}\right).$$

I'm not convinced of the utility of this expression, but it is an exact formulation consisting entirely of the input data, having a form similar to that used for average velocity.

I strongly urge anyone wishing to borrow this result to double-check my algebra and reasoning.

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The answer is: Yes, it is possible to formulate an exact expression which can reasonably be called average acceleration. What I have called the approximate acceleration at time $t_p$ is an exactly defined value derived from two average velocities. Applying the same method to two consecutive "approximate" accelerations gives the two forms

$$\left\langle \mathfrak{a}_{p}\right\rangle \equiv\frac{\mathfrak{a}_{p}-\mathfrak{a}_{p-1}}{\Delta t}$$

$$=\frac{1}{\Delta t^{2}}\left(\left\langle \mathfrak{v}_{p+1}\right\rangle -2\left\langle \mathfrak{v}_{p}\right\rangle +\left\langle \mathfrak{v}_{p-1}\right\rangle \right)$$

$$=\frac{1}{\Delta t^{3}}\left(\mathfrak{r}_{p+1}+3\left(\mathfrak{r}_{p-1}-\mathfrak{r}_{p}\right)-\mathfrak{r}_{p-2}\right).$$

I'm not convinced of the utility of this expression, but it is an exact formulation consisting entirely of the input data, having a form similar to that used for average velocity.

I strongly urge anyone wishing to borrow this result to double-check my algebra and reasoning.