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Aug 16, 2023 at 14:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 3, 2023 at 2:39 answer added SK Dash timeline score: 2
Mar 16, 2020 at 18:00 history tweeted twitter.com/StackPhysics/status/1239612585252655106
Oct 16, 2018 at 18:31 comment added Count Iblis The thermodynamic definition involves temperature, which is less fundamental than entropy. You can therefore simply define entropy in the usual information theoretical way and then define temperature for systems in equilibrium, so that the usual thermodynamical laws are valid.
Oct 16, 2018 at 18:11 answer added niels nielsen timeline score: 0
Oct 16, 2018 at 15:54 comment added user197851 This is essentially a duplicate of physics.stackexchange.com/questions/131170/… and many other questions on this site (not all of which have been answered satisfactorily). It is also discussed in any book or course on statistical thermodynamics. The issue, however, is still being discussed, see e.g. RH Swendsen Entropy, 19, 603 (2017).
Oct 16, 2018 at 12:30 answer added PhysicsDave timeline score: -3
Oct 16, 2018 at 12:30 comment added PhysicsDave I believe statistical entropy is more related to the mixing of gases which also infers a volume change by default. Once gases mix energy is lost to entropy, ex: if 2 1 liter vials of pure gas are connected they mix and each now occupies 2L.
Oct 16, 2018 at 12:21 history edited Qmechanic CC BY-SA 4.0
edited tags; edited title
Oct 16, 2018 at 12:20 review First posts
Oct 16, 2018 at 12:35
Oct 16, 2018 at 12:15 history asked user209836 CC BY-SA 4.0