Timeline for Heisenberg and Schrödinger pictures - clarification
Current License: CC BY-SA 4.0
7 events
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| Oct 1, 2020 at 14:18 | comment | added | AccidentalTaylorExpansion | @user3461126 When you are talking about time dependency in context of the Heisenberg and Schrodinger pictures you are talking about the time dependency that is caused by time evolution. You are basically asking "I have this time evolution operator $U(t)$, do I give this to the states or the operators?". The time dependency in $\frac{\partial A}{\partial t}$ does not come from $U(t)$ but from some external source. | |
| Jan 28, 2020 at 17:17 | comment | added | DanielSank | See here for example. | |
| Jan 28, 2020 at 17:16 | comment | added | DanielSank | Actually, it is pretty common for the Hamiltonian to depend on time in the Schrodinger picture. A system with some kind of applied drive will have a time dependent part, and in fact we often use the Heisenberg (or "interaction") picture to remove the time dependence of the drive. | |
| Oct 13, 2018 at 19:44 | comment | added | Kphysics | The answer is no, the Hamiltonian and any other operators can be time dependent already in the Schrödinger picture. An operator can even BECOME time independent in Heisenberg picture. The only thing for sure is that the wave function is time independent in Heisenberg picture! | |
| Oct 13, 2018 at 19:40 | history | edited | Kphysics | CC BY-SA 4.0 |
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| Oct 12, 2018 at 11:28 | comment | added | user3461126 | Aren't we exiting Schrödinger's picture when we are using those time-dependant formulas? | |
| Oct 12, 2018 at 11:23 | history | answered | Kphysics | CC BY-SA 4.0 |