I had the same question about a month ago when i tried to interprete the mathematics of electroweak SSB(sponteneous symmetry breaking). I investigated the obvious resolutions: either [1]maths is givining wrong interpretations or [2]It is giving correct interpretations.

Since Standard Model of EW interaction is so profound, I assumed [2] is coorrect.

So, what is the interpretation then if we analyze the math?

Consider this (understand in terms of fields, which are more fundamental than particles):

[a]Before SSB, above electroweak unification energy($E_{ew}$), we had 4 fields.

[b]At $E_{ew}$, these 4 fields starts interacting with each other and mixes in different combinations.

[c]After SSB, we have 4 new fields.

{$E_{ew}$ is about 246 GeV(approximately $10^{15}$ K, a temperature exceeded until shortly after the Big Bang)}

i.e., the real world is energy dependent. The cases [a], [b] and [c] do not exist together. The fields in [c] are completely new and its like resultant fields of combinations. And Our current stage of the universe falls under [c], therefore only [c] fields exist.

"what happens to W1, W2, W3 and B?" These fields do not exists in this stage of the universe.

"does that mean the W3 and B bosons are created for an instant and then mix to form a photon in the heart of a star?"

No!. Only photons are created directly. The reason is that W3 and B fileds do not exists in this stage and therefore we can't have W3 and B quanta. Only A and Z fields exists.

I had the same question about a month ago when i tried to interprete the mathematics of electroweak SSB(sponteneous symmetry breaking). I investigated the obvious resolutions: either [1]maths is givining wrong interpretations or [2]It is giving correct interpretations.

Since Standard Model of EW interaction is so profound, I assumed [2] is correct.

So, what is the interpretation then if we analyze the math?

Consider this (understand in terms of fields, which are more fundamental than particles):

[a]Before SSB, above electroweak unification energy($E_{ew}$), we had 4 fields.

[b]At $E_{ew}$, these 4 fields start interacting with each other and mix in different combinations.

[c]After SSB, we have 4 new fields.

{$E_{ew}$ is about 246 GeV(approximately $10^{15}$ K, a temperature exceeded until shortly after the Big Bang)}

i.e., the real world is energy dependent. The cases [a], [b] and [c] do not exist together. The fields in [c] are completely new and its like resultant fields of combinations. And Our current stage of the universe falls under [c], therefore only [c] fields exist.

"what happens to $W^1$, $W^2$, $W^3$ and $B$?" These fields do not exist in this stage of the universe.

"does that mean the $W^3$ and $B$ bosons are created for an instant and then mix to form a photon in the heart of a star?"

No!. Only photons are created directly. The reason is that $W^3$ and $B$ fields do not exist in this stage and therefore we can't have $W^3$ and $B$ quanta. Only $A$ and $Z$ fields exist.

I had the same question about a month ago when i tried to interprete the mathematics of electroweak SSB(sponteneous symmetry breaking). For me, the obvious resolutions were: either [1]maths is givining wrong interpretations or [2]It is giving correct interpretations.

Since we are getting everything correct using this maths, we must consider that this maths is telling the reality of physics and [2] is coorrect.

So, what is the interpretation then? Consider this (understand in terms of fields, which is more fundamental):

[a]Before SSB, above electroweak unification energy($E_{ew}$), we had 4 fileds.

[b]At $E_{ew}$, these 4 fields interact with each other and mixes in different combinations.

[c]After SSB, we have 4 new fields.

{$E_{ew}$ is about 246 GeV(approximately $10^{15}$ K, a temperature exceeded until shortly after the Big Bang)}

The real world is energy dependent. The cases [a], [b] and [c] do not exist together. The fields in [c] are completely new and its like resultant fields of combinations. And Our current stage of the universe falls under [c], therefore only [c] fields exist.

"what happens to W1, W2, W3 and B?" These fields do not exists in this stage of the universe.

"does that mean the W3 and B bosons are created for an instant and then mix to form a photon in the heart of a star?"

No!. Only photons are created directly because ,as mentioned above,the W3 and B fileds do not exist in this stage.

I had the same question about a month ago when i tried to interprete the mathematics of electroweak SSB(sponteneous symmetry breaking). I investigated the obvious resolutions: either [1]maths is givining wrong interpretations or [2]It is giving correct interpretations.

Since Standard Model of EW interaction is so profound, I assumed [2] is coorrect.

So, what is the interpretation then if we analyze the math?

Consider this (understand in terms of fields, which are more fundamental than particles):

[a]Before SSB, above electroweak unification energy($E_{ew}$), we had 4 fields.

[b]At $E_{ew}$, these 4 fields starts interacting with each other and mixes in different combinations.

[c]After SSB, we have 4 new fields.

{$E_{ew}$ is about 246 GeV(approximately $10^{15}$ K, a temperature exceeded until shortly after the Big Bang)}

i.e., the real world is energy dependent. The cases [a], [b] and [c] do not exist together. The fields in [c] are completely new and its like resultant fields of combinations. And Our current stage of the universe falls under [c], therefore only [c] fields exist.

"what happens to W1, W2, W3 and B?" These fields do not exists in this stage of the universe.

"does that mean the W3 and B bosons are created for an instant and then mix to form a photon in the heart of a star?"

No!. Only photons are created directly. The reason is that W3 and B fileds do not exists in this stage and therefore we can't have W3 and B quanta. Only A and Z fields exists.