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Oct 15, 2018 at 9:29 answer added Lorenz Mayer timeline score: 1
Oct 13, 2018 at 1:03 comment added Donkey Kong Thats exactly what I thought! Afterall, this is how the LW field is solved for in the first place. But, is that only for the point $x_0$ where the charge is located? Kind of like the static case ($\nabla \cdot E =0$ except at $x_0$)? Im just kind of confused what to expect!
Oct 12, 2018 at 16:40 comment added Lorenz Mayer shouldn't it satisfy $\nabla \cdot E = \delta(x-x_0)$, with $x_0$ the location of the source?
Oct 9, 2018 at 9:50 comment added Ján Lalinský Do you get non-zero divergence even for the case where $\beta'$ is zero all the time (rectilinear motion)?
Oct 9, 2018 at 3:11 history asked Donkey Kong CC BY-SA 4.0