Timeline for What is the highest possible frequency for an EM wave?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 12, 2019 at 9:17 | comment | added | ManRow | Yup, c/l gives a frequency of about 1.85e+43 Hz with about 1.23e+9 J per photon! Quite a lot of energy there ; ) | |
| Sep 1, 2017 at 22:54 | comment | added | user168013 | I'm sure that if that's the bound, then it must be unreachable as asymptote. So, we'd need infinite energy to make such a photon. | |
| Apr 8, 2015 at 9:00 | comment | added | thang | How do you get 6.2e34 hz? It's c/l, not 1/l. | |
| Sep 5, 2013 at 1:50 | comment | added | user4552 | @lurscher: It's not a paradox, because the answer doesn't assume string theory is correct. | |
| S Oct 30, 2012 at 18:27 | history | suggested | m0nhawk | CC BY-SA 3.0 |
added latex
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| Oct 30, 2012 at 18:17 | review | Suggested edits | |||
| S Oct 30, 2012 at 18:27 | |||||
| Oct 30, 2012 at 17:46 | comment | added | David Z | The Planck length isn't actually the smallest meaningful unit of distance - that's a widely held misconception. But it is theorized that there is some size below which any object collapses to a black hole, and that size is probably on the order of the Planck length. | |
| Oct 30, 2012 at 17:43 | comment | added | lurscher | well, but there you got a nice paradox: since string theory assumes that lorentz covariance is a perfect symmetry of the world, a single photon could have any energy, even greater than Planck energy. You need at least two photons to have a rest frame where a plancking black hole will form | |
| Oct 30, 2012 at 17:36 | history | migrated | from electronics.stackexchange.com (revisions) | ||
| Oct 30, 2012 at 16:38 | comment | added | Dave Tweed | I think you dropped a factor of c somewhere in your calculation. | |
| Oct 30, 2012 at 16:13 | history | answered | Stephen Collings | CC BY-SA 3.0 |