Timeline for Elevator moving near the speed of light
Current License: CC BY-SA 4.0
24 events
| when toggle format | what | by | license | comment | |
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| Sep 30, 2021 at 21:35 | vote | accept | okcapp | ||
| Sep 11, 2021 at 1:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 13, 2021 at 22:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
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| May 11, 2020 at 19:07 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
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| Sep 3, 2019 at 12:00 | history | tweeted | twitter.com/StackPhysics/status/1168856244045660161 | ||
| Sep 2, 2019 at 17:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 3, 2019 at 4:18 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
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| Aug 3, 2019 at 4:04 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 27, 2018 at 5:05 | review | First posts | |||
| Sep 27, 2018 at 5:49 | |||||
| Sep 7, 2018 at 20:25 | comment | added | okcapp | @PM 2Ring Yes it is! Thanks for the clear question. I suppose if I could rewrite my question I would ask how spacetime curvature would appear to a person jumping from the sidewalk, the person jumping from the constant velocity elevator (moving at a speed close to the speed of light), and to an observer sitting on the sidewalk watch all of the activity. | |
| Sep 7, 2018 at 15:40 | comment | added | PM 2Ring | The spacetime curvature doesn't change, per se, but you do need to take time dilation & length contraction into account when comparing what the curvature "looks" like to different observers. Is that what you're asking about? | |
| Sep 7, 2018 at 15:08 | history | edited | okcapp | CC BY-SA 4.0 |
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| Sep 7, 2018 at 8:15 | history | edited | user191954 |
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| Sep 7, 2018 at 8:05 | answer | added | Anonymous Cats | timeline score: 0 | |
| Sep 7, 2018 at 7:17 | answer | added | StephenG - Help Ukraine | timeline score: 0 | |
| Sep 7, 2018 at 5:11 | comment | added | okcapp | @PM 2Ring I agree that over any appreciable interval of time the -9.8 will not be applicable. But I believe the reason you have in mind for this is the fact that the distance from the center of the earth will change extremely rapidly. If I'm correct about your thought then I do agree with you. Nonetheless, I'm curious about the limiting case where the interval of time is approaching zero (this interval I have in mind is right as the clock just started ticking post-jump). Can gravity "transmit the -9.8 acceleration" even as the initial velocity has such an overwhelmingly large magnitude? | |
| Sep 7, 2018 at 3:50 | comment | added | PM 2Ring | The acceleration won't stay constant if you're moving vertically at that speed. The Earth's diameter is about 0.021 light-seconds. | |
| Sep 7, 2018 at 3:34 | history | edited | okcapp | CC BY-SA 4.0 |
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| Sep 7, 2018 at 3:09 | history | edited | okcapp | CC BY-SA 4.0 |
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| Sep 7, 2018 at 1:31 | history | edited | okcapp | CC BY-SA 4.0 |
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| Sep 7, 2018 at 1:02 | history | asked | okcapp | CC BY-SA 4.0 |