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V.F.
V.F.
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For DC (ignoring secondary effects), the resistance would be about the same.

For AC, the resistance of the hollow conductor will be lower due to the skin effect. The higher AC frequency, which causes the more beneficial thin walls will be, provided,density of courseAC current to increase toward the surface of a conductor.

For a solid conductor, thatthis would lead to the effective reduction of the active cross-section area is preservedand therefore, to the increased resistance. For a hollow conductor, this would not make as much difference.

As the frequency increases, the skin depth (the layer under the surface of a conductor where most of the current will concentrate) decreases, which further benefits the hollow conductor.

For DC (ignoring secondary effects), the resistance would be about the same.

For AC, the resistance of the hollow conductor will be lower due to the skin effect. The higher AC frequency, the more beneficial thin walls will be, provided, of course, that the cross-section area is preserved.

For DC (ignoring secondary effects), the resistance would be about the same.

For AC, the resistance of the hollow conductor will be lower due to the skin effect, which causes the density of AC current to increase toward the surface of a conductor.

For a solid conductor, this would lead to the effective reduction of the active cross-section area and therefore, to the increased resistance. For a hollow conductor, this would not make as much difference.

As the frequency increases, the skin depth (the layer under the surface of a conductor where most of the current will concentrate) decreases, which further benefits the hollow conductor.

Source Link
V.F.
V.F.
  • 12.3k
  • 3
  • 17
  • 34

For DC (ignoring secondary effects), the resistance would be about the same.

For AC, the resistance of the hollow conductor will be lower due to the skin effect. The higher AC frequency, the more beneficial thin walls will be, provided, of course, that the cross-section area is preserved.