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Sep 6, 2018 at 17:09 answer added A.V.S. timeline score: 2
Sep 6, 2018 at 13:08 comment added Maximko Well, this is exactly what I don't understand. If there is a background scalar field, then the spherically-symmetric solution is the Janis-Newman-Winicour metric which has no horizons (journals.aps.org/prd/abstract/10.1103/PhysRevD.31.1280). It is not the same as a piece of dust falling into already formed Schwarzschild BH.
Sep 6, 2018 at 12:54 comment added Javier If a black hole is by definition a vacuum solution, doesn't it stop being a black hole as soon as the tiniest piece of dust falls inside? A black hole is a region of spacetime not casually connected to null infinity, i.e., a place from where not even light can escape. This is a more general and more useful definition.
Sep 6, 2018 at 8:13 history asked Maximko CC BY-SA 4.0