Timeline for Using Wick Rotation to calculate Generating Function in Minkowski Space
Current License: CC BY-SA 4.0
4 events
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Aug 31, 2018 at 14:04 | comment | added | yalda | @TaylorTiger $p$ is not naturlly a covector. However, the component of the corresponding covector is what is needed when computing the inner product $x\cdot p = x^\mu p_\mu \equiv x^0 p_0 + \vec{x} \cdot \vec{p}$. The thing is, that when you are in euclidean space the components of the covectors and vectors are the same, so index position does not matter. However, after the Wick rotation you are in Minkowski space and there the position of the index plays an important role. | |
Aug 30, 2018 at 18:28 | comment | added | user148792 | Interesting... I'm wondering why is p a covariant vector? Before the transformation p is just defined (in the middle of page 14 of the document in the link) to be the Fourier Transformation pair of x, but Cardy never mentioned that it is a covariant vector. | |
Aug 30, 2018 at 14:40 | review | First posts | |||
Aug 30, 2018 at 17:38 | |||||
Aug 30, 2018 at 14:36 | history | answered | yalda | CC BY-SA 4.0 |