Timeline for Is Feynman wrong about the principle of virtual work to find forces in a dielectric?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 18, 2022 at 17:08 | answer | added | Dave Craig | timeline score: 0 | |
| Jan 28, 2020 at 3:59 | answer | added | polytheneman | timeline score: 0 | |
| Sep 6, 2018 at 4:46 | vote | accept | Steven Thomas Hatton | ||
| Sep 6, 2018 at 3:37 | answer | added | Steven Thomas Hatton | timeline score: 0 | |
| Aug 25, 2018 at 8:24 | history | edited | Steven Thomas Hatton | CC BY-SA 4.0 |
changed emphasis
|
| Aug 24, 2018 at 20:20 | comment | added | Steven Thomas Hatton | Why do you speak of a Lagrangian? Because I quoted from a book on Lagrangian dynamics? That is a field much broader than the application of the Euler-Lagrange equation to a Lagrangian function. It includes the topic of virtual work. A virtual displacement would not would not require stresses on the components of the hypothetical object. What Feynman is applying is the principle of actual work. | |
| Aug 24, 2018 at 17:11 | comment | added | lalala | I think Feynman is using virtual work and not using s Lagrangian, but his argument is about actual work and energy conservation. | |
| Aug 24, 2018 at 16:10 | history | edited | Steven Thomas Hatton | CC BY-SA 4.0 |
Added quoteation from Wells's Lagrangina Dynamics
|
| Aug 24, 2018 at 14:20 | comment | added | drvrm | <Virtual work is the total work done by the applied forces and the inertial forces of a mechanical system as it moves through a set of virtual displacements. When considering forces applied to a body in static equilibrium, the principle of least action requires the virtual work of these forces to be zero.> moreover the virtual displacements are consistent with the constraining forces such that Fc.dr =0, thereby Feynman'sapproach seems good. | |
| Aug 24, 2018 at 11:45 | history | asked | Steven Thomas Hatton | CC BY-SA 4.0 |