I assume you mean time independent perturbation theory. This book by David McIntyre is a great introduction to quantum mechanics (I used it as a supplement to Griffiths'). I especially like how McIntyre uses spin-1/2 as a working example to define the basic concepts of quantum mechanics, and his chapters on perturbation theory are clear and concise.

Below, I describe how to find the first order and second order corrections to energies and energy eigenstates/eigenkets. When $H$ is degenerate, one has to locate the degenerate subspace of $H$ and work with that directly.

For non-degenerate perturbation theory:

Our original Hamiltonian, $H$, and our perturbed Hamiltonian, $H'$, then we have the eigenvalue equation,

$$ H |n^{(0)} = E^{(0)}_{n} |n^{(0)}> $$

where the superscript denotes the order of the correction, i.e. (0) denotes the unperturbed system.

So we may expand the energies in terms of the energy corrections,

$$ E_{n} = E^{(1)}_{n} + E^{(2)}_{n} + ...$$

and the energy eigenkets,

$$ |n> = |n^{(0)}> + |n^{(1)}> + ...$$

So, the elements of the perturbed Hamiltonian are given by

$$ H'_{n,n} = <n^{(0)}|H'|n^{(0)}> = E^{(1)}_{n} .$$

It can be shown, by taking advantage of the properties of the inner product, that the other energies and the eigenket corrections are

$$ E_{n}^{(2)} = \sum\lim_{m \neq n} \frac{|<m^{(0)} | H' | n^{(0)}>|^{2}}{E_{n}^{(0)} - E_{m}^{(0)}},$$

$$ |n^{(1)}> = \sum\lim_{m \neq n} \frac{<m^{(0)} | H' | n^{(0)}>}{E_{n}^{(0)} - E_{m}^{(0)}} |m^{(0)}>.$$

Sorry the math looks bad, I'm not sure how to use Dirac notation on this website.

For degenerate perturbation theory:

So, of course, the degenerate subspace of $H$ in your question is of smaller dimensionality than $H$. This means that not every eigenstate needs a correction! Since you've located the degenerate subspace, now you need to diagonalize the perturbation Hamiltonian $H'$ in the degenerate subspace to obtain the corrections to the original eigenkets. Page 339 of McIntyre's book goes over several examples.

If McIntyre's book is not available to you, this website is helpful.

I assume you mean time independent perturbation theory. This book by David McIntyre is a great introduction to quantum mechanics (I used it as a supplement to Griffiths'). I especially like how McIntyre uses spin-1/2 as a working example to define the basic concepts of quantum mechanics, and his chapters on perturbation theory are clear and concise.

Below, I describe how to find the first order and second order corrections to energies and energy eigenstates/eigenkets. When $H$ is degenerate, one has to locate the degenerate subspace of $H$ and work with that directly.

For non-degenerate perturbation theory:

Our original Hamiltonian, $H$, and our perturbed Hamiltonian, $H'$, then we have the eigenvalue equation,

$$ H |n^{(0)}\rangle = E^{(0)}_{n} |n^{(0)}\rangle $$

where the superscript denotes the order of the correction, i.e. (0) denotes the unperturbed system.

So we may expand the energies in terms of the energy corrections,

$$ E_{n} = E^{(1)}_{n} + E^{(2)}_{n} + ...$$

and the energy eigenkets,

$$ |n\rangle = |n^{(0)}\rangle + |n^{(1)}\rangle + ...$$

So, the elements of the perturbed Hamiltonian are given by

$$ H'_{n,n} = \langle n^{(0)}|H'|n^{(0)}\rangle = E^{(1)}_{n} .$$

It can be shown, by taking advantage of the properties of the inner product, that the other energies and the eigenket corrections are

$$ E_{n}^{(2)} = \sum\lim_{m \neq n} \frac{|\langle m^{(0)} | H' | n^{(0)}\rangle|^{2}}{E_{n}^{(0)} - E_{m}^{(0)}},$$

$$ |n^{(1)}\rangle = \sum\lim_{m \neq n} \frac{\langle m^{(0)} | H' | n^{(0)}\rangle}{E_{n}^{(0)} - E_{m}^{(0)}} |m^{(0)}\rangle.$$

For degenerate perturbation theory:

So, of course, the degenerate subspace of $H$ in your question is of smaller dimensionality than $H$. This means that not every eigenstate needs a correction! Since you've located the degenerate subspace, now you need to diagonalize the perturbation Hamiltonian $H'$ in the degenerate subspace to obtain the corrections to the original eigenkets. Page 339 of McIntyre's book goes over several examples.

If McIntyre's book is not available to you, this website is helpful.

I assume you mean time independent perturbation theory. This book by David McIntyre is a great introduction to quantum mechanics (I used it as a supplement to Griffiths'). I especially like how McIntyre uses spin-1/2 as a working example to define the basic concepts of quantum mechanics, and his chapters on perturbation theory are clear and concise.

Below, I describe how to find the first order and second order corrections to energies and energy eigenstates/eigenkets. When $H$ is degenerate, one has to locate the degenerate subspace of $H$ and work with that directly.

For non-degenerate perturbation theory:

Our original Hamiltonian, $H$, and our perturbed Hamiltonian, $H'$, then we have the eigenvalue equation,

$$ H |n^{(0)} = E^{(0)}_{n} |n^{(0)}> $$

where the superscript denotes the order of the correction, i.e. (0) denotes the unperturbed system.

So we may expand the energies in terms of the energy corrections,

$$ E_{n} = E^{(1)}_{n} + E^{(2)}_{n} + ...$$

and the energy eigenkets,

$$ |n> = |n^{(0)}> + |n^{(1)}> + ...$$

So, the elements of the perturbed Hamiltonian are given by

$$ H'_{n,n} = <n^{(0)}|H'|n^{(0)}> = E^{(1)}_{n} .$$

It can be shown, by taking advantage of the properties of the inner product, that the other energies and the eigenket corrections are

$$ E_{n}^{(2)} = \sum\lim_{m \neq n} \frac{|<m^{(0)} | H' | n^{(0)}>|^{2}}{E_{n}^{(0)} - E_{m}^{(0)}},$$

$$ |n^{(1)}> = \sum\lim_{m \neq n} \frac{<m^{(0)} | H' | n^{(0)}>}{E_{n}^{(0)} - E_{m}^{(0)}} |m^{(0)}>.$$

Sorry the math looks bad, I'm not sure how to use Dirac notation on this website.

For degenerate perturbation theory:

So, of course, the degenerate subspace of $H$ in your question is of smaller dimensionality than $H$. This means that not every eigenstate needs a correction! Since you've located the degenerate subspace, now you need to diagonalize the perturbation Hamiltonian $H'$ in the degenerate subspace to obtain the corrections to the original eigenkets. Page 339 of McIntyre's book goes over several examples.

I assume you mean time independent perturbation theory. This book by David McIntyre is a great introduction to quantum mechanics (I used it as a supplement to Griffiths'). I especially like how McIntyre uses spin-1/2 as a working example to define the basic concepts of quantum mechanics, and his chapters on perturbation theory are clear and concise.

Below, I describe how to find the first order and second order corrections to energies and energy eigenstates/eigenkets. When $H$ is degenerate, one has to locate the degenerate subspace of $H$ and work with that directly.

For non-degenerate perturbation theory:

Our original Hamiltonian, $H$, and our perturbed Hamiltonian, $H'$, then we have the eigenvalue equation,

$$ H |n^{(0)} = E^{(0)}_{n} |n^{(0)}> $$

where the superscript denotes the order of the correction, i.e. (0) denotes the unperturbed system.

So we may expand the energies in terms of the energy corrections,

$$ E_{n} = E^{(1)}_{n} + E^{(2)}_{n} + ...$$

and the energy eigenkets,

$$ |n> = |n^{(0)}> + |n^{(1)}> + ...$$

So, the elements of the perturbed Hamiltonian are given by

$$ H'_{n,n} = <n^{(0)}|H'|n^{(0)}> = E^{(1)}_{n} .$$

It can be shown, by taking advantage of the properties of the inner product, that the other energies and the eigenket corrections are

$$ E_{n}^{(2)} = \sum\lim_{m \neq n} \frac{|<m^{(0)} | H' | n^{(0)}>|^{2}}{E_{n}^{(0)} - E_{m}^{(0)}},$$

$$ |n^{(1)}> = \sum\lim_{m \neq n} \frac{<m^{(0)} | H' | n^{(0)}>}{E_{n}^{(0)} - E_{m}^{(0)}} |m^{(0)}>.$$

Sorry the math looks bad, I'm not sure how to use Dirac notation on this website.

For degenerate perturbation theory:

So, of course, the degenerate subspace of $H$ in your question is of smaller dimensionality than $H$. This means that not every eigenstate needs a correction! Since you've located the degenerate subspace, now you need to diagonalize the perturbation Hamiltonian $H'$ in the degenerate subspace to obtain the corrections to the original eigenkets. Page 339 of McIntyre's book goes over several examples.

If McIntyre's book is not available to you, this website is helpful.