Timeline for Why we use $L_2$ Space In QM?
Current License: CC BY-SA 3.0
17 events
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Apr 13, 2017 at 12:39 | history | edited | CommunityBot |
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Oct 29, 2012 at 16:40 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
added explanation in response to comment by MBN
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Oct 29, 2012 at 14:46 | comment | added | Ron Maimon | @A.O.Tell: I agree with this--- it would make a fine answer BTW. | |
Oct 29, 2012 at 12:40 | comment | added | MBN | Point 3. is not phrased well. "to make the Hilbert space complete", Hilbert spaces are complete. May be it should say "so that the space of states is complete" or something like that. | |
Oct 27, 2012 at 15:10 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Oct 27, 2012 at 6:55 | comment | added | A.O.Tell | @RonMaimon, I'm very aware of all that, and it's why I called the physical reasons a starting point. And that's all it is. Without the physics you wouldn't have a reason to consider this norm or inner product. I'm not saying that the mathematical constructions entirely follow from physical principles, only that they are motivated. | |
Oct 26, 2012 at 21:31 | comment | added | Ron Maimon | @A.O.Tell: I don't think you realize what kind of functions are contained in L_2. This space includes wavefunctions which are completely fractally supported, discontinuous everywhere, with infinite expected energy, infinite energy variance, ridiculous unphysical propagation, and so on. L2 is an idealization which has very little to do with physics, but with the type of closure operations mathematicians like to make. The idealization physicists make is a lattice, with the limit of finite energy wavefunctions. That's not the same as L2, but so what, the mathematicians can do whatever they want. | |
Oct 26, 2012 at 15:28 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Oct 26, 2012 at 9:59 | comment | added | A.O.Tell | These are all good mathematical reasons, but in my eyes the most important reasons are of physical nature: The Schroedinger equation preserves the 2-norm, and probabilities are related to an inner product that induce this norm. So the mathematical framework for quantum theory is naturally based on these sensible starting points. | |
Oct 26, 2012 at 0:00 | comment | added | Ron Maimon | @TMS: I just mean make space discrete, make a grid of positions, and then there is no difference between the different $L_p$ spaces. All the issues are with what completions you are considering when the grid is eensy teensy, and this is not physics, but pure mathematics. The "right" completion is L_2, but so what, who cares. I don't know a reference, the lattice version is just something you work out on your own, but all physicists imagine a lattice down there anyway, just to regulate things like delta-functions and infinite volume limits, which are only interesting to mathematicians. | |
Oct 25, 2012 at 23:31 | comment | added | TMS | @Ron: can you please explain or provide a reference to understand what you mean by need for limit +1? it's sounds to me something equivalent to the completeness, no? | |
Oct 25, 2012 at 23:29 | vote | accept | TMS | ||
Oct 25, 2012 at 23:28 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Oct 25, 2012 at 23:28 | comment | added | TMS | thx for detailed answer, then we using it just because it feels to be natural, anyway can you please explain why not all $L_p$ spaces Hilbert spaces, and what you mean by "It is true that other Hilbert space (modeled over the position space R3) do exist, but they would typically rely on additional structure" | |
Oct 25, 2012 at 23:25 | comment | added | Ron Maimon | One should add that this is for mathematical convenience in the small lattice limit, which is technically unphysical. For any lattice spacing, it is irrelevant which L space you use, since the topology is the same, but L2 gives the convenient limit, +1 anyway. | |
Oct 25, 2012 at 23:22 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Oct 25, 2012 at 23:17 | history | answered | Qmechanic♦ | CC BY-SA 3.0 |