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Philip Wood
Philip Wood
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With that equation you get the net change in angular momentum of the system to be zero. In that case you can resolve the net force into an applied force that acts on the total mass, and does not produce any rotation. Think snooker. If you hit the queuecue against the ball dead center then you don't get spin. But if you are off center then you get spin, and the force is partially going to produce motion of the mass of the ball, and partially produce rotation.

With that equation you get the net change in angular momentum of the system to be zero. In that case you can resolve the net force into an applied force that acts on the total mass, and does not produce any rotation. Think snooker. If you hit the queue against the ball dead center then you don't get spin. But if you are off center then you get spin, and the force is partially going to produce motion of the mass of the ball, and partially produce rotation.

With that equation you get the net change in angular momentum of the system to be zero. In that case you can resolve the net force into an applied force that acts on the total mass, and does not produce any rotation. Think snooker. If you hit the cue against the ball dead center then you don't get spin. But if you are off center then you get spin, and the force is partially going to produce motion of the mass of the ball, and partially produce rotation.

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user93146
user93146

With that equation you get the net change in angular momentum of the system to be zero. In that case you can resolve the net force into an applied force that acts on the total mass, and does not produce any rotation. Think snooker. If you hit the queue against the ball dead center then you don't get spin. But if you are off center then you get spin, and the force is partially going to produce motion of the mass of the ball, and partially produce rotation.