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Bounty Ended with 100 reputation awarded by Peter4075
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knzhou
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It's indeed pretty annoying how many conventions there are. I'll tryIn the first expression:

  • $R$ has dimensions of length
  • $r$ and $k$ have no dimensions
  • $k$ is scaled so it's $-1$, $0$, or $1$

To go from the first expression to be as explicit as possiblethe second expression, but feel freewe define $$r' = r R_0, \quad k' = k / R_0^2, \quad a(t) = R(t) / R_0$$ where I'm denoting the new variables with a prime just to askbe extra clear. Then

  • $r'$ has dimensions of length and $k'$ has dimensions of inverse length squared
  • $a$ has no dimensions

These are the two main conventions for more detailsthe FRW metric. Your third example is a bit unusual, because it tries to set $k'$ to $-1$, $0$, or $1$, which doesn't make any sense because $k'$ has dimensions.

InHowever, $k'$ is a constant, so we can use it to define our unit of length. Taking positive curvature for concreteness, this means that rather than measuring lengths in meters, we measure in a unit system where the first expression:numeric value of $k'$ is $1 \, (\text{length unit})^{-2}$. Another way of saying this is that this example is setting $k' = 1$ in the same sense that you may set $c = 1$ in special relativity. You can always do this by defining your unit system appropriately, but then naive dimensional analysis will stop working, and you'll have to put the $k'$'s and $c$'s back in at the end to get valid numbers out.

It's indeed pretty annoying how many conventions there are. I'll try to be as explicit as possible, but feel free to ask for more details.

In the first expression:

In the first expression:

  • $R$ has dimensions of length
  • $r$ and $k$ have no dimensions
  • $k$ is scaled so it's $-1$, $0$, or $1$

To go from the first expression to the second expression, we define $$r' = r R_0, \quad k' = k / R_0^2, \quad a(t) = R(t) / R_0$$ where I'm denoting the new variables with a prime just to be extra clear. Then

  • $r'$ has dimensions of length and $k'$ has dimensions of inverse length squared
  • $a$ has no dimensions

These are the two main conventions for the FRW metric. Your third example is a bit unusual, because it tries to set $k'$ to $-1$, $0$, or $1$, which doesn't make any sense because $k'$ has dimensions.

However, $k'$ is a constant, so we can use it to define our unit of length. Taking positive curvature for concreteness, this means that rather than measuring lengths in meters, we measure in a unit system where the numeric value of $k'$ is $1 \, (\text{length unit})^{-2}$. Another way of saying this is that this example is setting $k' = 1$ in the same sense that you may set $c = 1$ in special relativity. You can always do this by defining your unit system appropriately, but then naive dimensional analysis will stop working, and you'll have to put the $k'$'s and $c$'s back in at the end to get valid numbers out.

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knzhou
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  • 494

It's indeed pretty annoying how many conventions there are. I'll try to be as explicit as possible, but feel free to ask for more details.

In the first expression: