Timeline for Why does the scalar field still have a VEV in a vacuum state of a SUSY-theory?
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| Jun 26, 2018 at 14:39 | vote | accept | Graphite | ||
| Jun 26, 2018 at 11:38 | history | edited | Qmechanic♦ |
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| Jun 26, 2018 at 11:32 | answer | added | Toffomat | timeline score: 4 | |
| Jun 26, 2018 at 11:22 | comment | added | Graphite | Do you mean the variation of the fermionic field under Lorentz transformations? Because that is zero for sure, by definition. Or do you mean the transformation of the scalar field under susy that becomes a fermionic field? That depends a bit on dimension and what kind of multiplet you're in but for example in 4d N=1 in a chiral multiplet the transformation is $\delta \sigma \propto \epsilon^{\alpha} \psi_{\alpha}$ where $\sigma$ is the scalar field, $\psi$ the fermionic field and $\epsilon$ the spinorial infinitesimal parameter. (See lectures by Bertolini on SUSY, 4.59) | |
| Jun 26, 2018 at 11:14 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
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| Jun 26, 2018 at 10:40 | comment | added | knzhou | Have you tried explicitly calculating the variation of the fermion field? | |
| Jun 26, 2018 at 9:50 | history | asked | Graphite | CC BY-SA 4.0 |