Timeline for Why is the normal force a hypotenuse of the weight force? Isn't it a component of the weight force?
Current License: CC BY-SA 4.0
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| Jun 5, 2018 at 8:47 | comment | added | Global | I am saying draw a perpendicular to the hypotenuse. Take it as (say) Y axis and then take the hypotenuse itself as X axis. So now you have a new coordinate system. After this resolve the Horizontal applied force along these new X and Y coordinates. Then take the Gravitational force, F=m*g and resolve it along the X and Y axes. Then equate the various forces along X axis to get the answer. (Be aware to mark the angles APPROPRIATELY while resolving the applied horizontal force and the gravitational force, which is why you are getting a wrong answer. ) | |
| Jun 5, 2018 at 8:31 | comment | added | Varun Jahagirdar | I think I tried to do what you are suggesting but it gave me the wrong answer. I'm not entirely sure what you are trying to say | |
| Jun 5, 2018 at 7:16 | history | answered | Global | CC BY-SA 4.0 |