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Valter Moretti
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No, because when expanding $L_k$ you see that only components $X_k$ and $P_h$ with $h \neq k$ enter the formula, and they commute. So you can safely use the classical definition also in QM and the symmetrised formula would produce the same result.

No, because when expanding $L_k$ you see that only components $X_k$ and $P_h$ with $h \neq k$ enter the formula, and they commute. So you can safely use the classical definition also in QM.

No, because when expanding $L_k$ you see that only components $X_k$ and $P_h$ with $h \neq k$ enter the formula, and they commute. So you can safely use the classical definition also in QM and the symmetrised formula would produce the same result.

Source Link
Valter Moretti
  • 78k
  • 8
  • 169
  • 308

No, because when expanding $L_k$ you see that only components $X_k$ and $P_h$ with $h \neq k$ enter the formula, and they commute. So you can safely use the classical definition also in QM.