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May 24, 2018 at 8:27 history edited Nat CC BY-SA 4.0
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May 24, 2018 at 7:11 answer added JamalS timeline score: 1
May 23, 2018 at 18:29 comment added user93237 I think that you may be somehow confusing this situation with the idea of a position vector described in $(r,\theta)$ coordinates. In that case, if r=0, then the position vector is equal to zero regardless of the value of $\theta$.
May 23, 2018 at 18:27 answer added curio timeline score: 1
May 23, 2018 at 18:16 comment added garyp No, the $\theta$ component is $U_\theta (r)$. It's a number that depends on $r$, and $r$ has a well defined value at every point in space. Remember: nowhere is it said that $r$ is constrained to be zero.
May 23, 2018 at 18:14 comment added Robbe Motmans I understand, but if the $r$ component is zero, doesn't this mean that the $\theta$ component is zero?
May 23, 2018 at 18:09 comment added garyp This vector field does not say that $r$ is always zero. It says that the $r$ component of every vector in the field is zero.
May 23, 2018 at 18:01 review First posts
May 23, 2018 at 20:33
May 23, 2018 at 17:59 history asked Robbe Motmans CC BY-SA 4.0