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May 21, 2018 at 10:47 vote accept jarhead
May 21, 2018 at 10:14 comment added Gec @jarhead, I think you are doing something wrong. I get the same result when solving integrals.
May 21, 2018 at 5:50 comment added jarhead @Gec, I do not get the same result when solving the integral with the delta function, so I'm not convinced that your argument holds.
May 20, 2018 at 16:36 comment added Gec @jarhead, I updated my answer.
May 20, 2018 at 16:35 history edited Gec CC BY-SA 4.0
The answer is updated
May 20, 2018 at 15:57 comment added jarhead @Gec, can you elaborate more on the symmetry? I'll accept your answer, but it is not clear to me why due to the delta function you obtain $<p^2>+<q^2>=E$
May 20, 2018 at 15:34 comment added jarhead @JamalS, this is a matter of definition.
May 20, 2018 at 10:30 comment added JamalS Yes, it should be, since $H=\dots + \frac12 m \omega^2 x^2$, and so for $m=2$, you have $\omega^2 x^2$.
May 20, 2018 at 8:50 history answered Gec CC BY-SA 4.0