Timeline for How can I derive the stress tensor for a Newtonian fluid in more physical terms?
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Oct 25 at 15:09 | vote | accept | MichaelW | ||
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Dec 18, 2023 at 21:37 | answer | added | john | timeline score: 0 | |
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Dec 21, 2018 at 23:28 | comment | added | Kyle Kanos | Related, if not dupe of, physics.stackexchange.com/q/152927/25301 | |
Dec 21, 2018 at 20:46 | history | edited | Qmechanic♦ |
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Dec 21, 2018 at 18:47 | answer | added | aghostinthefigures | timeline score: 1 | |
May 17, 2018 at 1:36 | history | tweeted | twitter.com/StackPhysics/status/996927289425317888 | ||
May 16, 2018 at 21:00 | comment | added | DWade64 | because there is no comparison. It's a completely different way of thinking | |
May 16, 2018 at 21:00 | comment | added | DWade64 | With points, you can say "there exists a force at this point in a given direction." With continuous matter, we have to get used to 1) force densities (read forces per unit area) because that's the only thing that makes sense in this context (force at points in continuum don't make sense. Define force density just as mass density makes more sense than mass for a continuum. How much mass is located at a point in a fluid?) and 2) that these force densities vary with direction. Point 2 is harder to understand intuitively. Especially if you try relating this to introductory physics | |
May 16, 2018 at 20:43 | comment | added | DWade64 | This might or might not help. Also, this might or might not be correct. At the end of the day, the reason why things get confusing is because of the philosophical differences between "continuous mathematics" and "discrete mathematics." In physics, we start off studying discrete systems (i.e. particles). Applying "continuous math" (read derivatives/integrals/continuous number lines) to "discrete particles" is much much easier than applying "continuous math" to "continuous systems." The fundamental difference is the difference between points in 3D space and infinitesimal regions in 3D space | |
May 16, 2018 at 18:59 | history | edited | MichaelW | CC BY-SA 4.0 |
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May 16, 2018 at 11:56 | comment | added | Chet Miller | The reason for the complicated mathematics is to guarantee that the state of stress that the law describes must be independent of the motion of the observer (which, of course, can not affect the state of stress in a fluid), even including rigid body rotations of the observer. Basically, Newton's empirical law of viscosity says that the state of stress in a fluid must be a linear function of the components of the velocity gradient tensor. The constant of proportionality is backed out by considering the case of only a single component to the velocity gradient, and matching to that case. | |
May 16, 2018 at 10:49 | history | edited | MichaelW | CC BY-SA 4.0 |
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May 16, 2018 at 10:43 | history | asked | MichaelW | CC BY-SA 4.0 |