Skip to main content
Physics

Return to Question

Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
Bumped by Community user
added 72 characters in body
Source Link
Nat
Nat
  • 4.7k
  • 4
  • 25
  • 37

From "Introduction to Electrodynamics" by David J. Griffiths Electrodynamics example, Example 12.13:

"Consider a rectangular loop of wire carrying a steady current I . Picture the current as a stream of noninteracting positive charges that move freely within the wire. When a uniform electric field E is applied, the charges accelerate in the left segment and decelerate in the right one."

Consider a rectangular loop of wire carrying a steady current $I$. Picture the current as a stream of noninteracting positive charges that move freely within the wire. When a uniform electric field $\mathbf{E}$ is applied, the charges accelerate in the left segment and decelerate in the right one.

Afterwards he says:

"The current (I = λu) is the same in all four segments (or else charge would be piling up somewhere)"

The current $\left(I = \lambda u\right)$ is the same in all four segments (or else charge would be piling up somewhere)

I'm assuming he is referring to the current after the influence of the electric field. Is it obvious that the current remains constant after the influence of the electric field? Why is it so? What does the "piling up" mean?

enter image description here

enter image description here

Griffiths Electrodynamics example 12.13

"Consider a rectangular loop of wire carrying a steady current I . Picture the current as a stream of noninteracting positive charges that move freely within the wire. When a uniform electric field E is applied, the charges accelerate in the left segment and decelerate in the right one."

Afterwards he says:

"The current (I = λu) is the same in all four segments (or else charge would be piling up somewhere)"

I'm assuming he is referring to the current after the influence of the electric field. Is it obvious that the current remains constant after the influence of the electric field? Why is it so? What does the "piling up" mean?

enter image description here

From "Introduction to Electrodynamics" by David J. Griffiths, Example 12.13:

Consider a rectangular loop of wire carrying a steady current $I$. Picture the current as a stream of noninteracting positive charges that move freely within the wire. When a uniform electric field $\mathbf{E}$ is applied, the charges accelerate in the left segment and decelerate in the right one.

Afterwards he says:

The current $\left(I = \lambda u\right)$ is the same in all four segments (or else charge would be piling up somewhere)

I'm assuming he is referring to the current after the influence of the electric field. Is it obvious that the current remains constant after the influence of the electric field? Why is it so? What does the "piling up" mean?

enter image description here

Source Link
Asanovic Tomas
Asanovic Tomas
  • 85
  • 7

Current in Square loop under electric field

Griffiths Electrodynamics example 12.13

"Consider a rectangular loop of wire carrying a steady current I . Picture the current as a stream of noninteracting positive charges that move freely within the wire. When a uniform electric field E is applied, the charges accelerate in the left segment and decelerate in the right one."

Afterwards he says:

"The current (I = λu) is the same in all four segments (or else charge would be piling up somewhere)"

I'm assuming he is referring to the current after the influence of the electric field. Is it obvious that the current remains constant after the influence of the electric field? Why is it so? What does the "piling up" mean?

enter image description here