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Archisman Panigrahi
Archisman Panigrahi
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The relation $L'=\gamma L$ is correct. $L$ is the length of the moving object from $R$ frame, which is shorter than $L'$, which is the length of the object measured in a frame which is moving with the object, i.e. the object is stationary in that frame. So, the stationary length of the object is $L'$, which is greater than $L$, the length of the moving object.

Since $L' > L$, the length of a moving object contracts.

The relation $L'=\gamma L$ is correct. $L$ is the length of the moving object from $R$ frame, which is shorter than $L'$, which is the length of the object measured in a frame which is moving with the object, i.e. the object is stationary in that frame. So, the stationary length of the object is $L'$, which is greater than $L$, the length of the moving object.

The relation $L'=\gamma L$ is correct. $L$ is the length of the moving object from $R$ frame, which is shorter than $L'$, which is the length of the object measured in a frame which is moving with the object, i.e. the object is stationary in that frame. So, the stationary length of the object is $L'$, which is greater than $L$, the length of the moving object.

Since $L' > L$, the length of a moving object contracts.

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Archisman Panigrahi
Archisman Panigrahi
  • 3.3k
  • 21
  • 41

The relation $L'=\gamma L$ is correct. $L$ is the length of the moving object from $R$ frame, which is shorter than $L'$, which is the length of the object measured in a frame which is moving with the object, i.e. the object is stationary in that frame. So, the stationary length of the object is $L'$, which is greater than $L$, the length of the moving object.