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May 1, 2018 at 13:39 comment added safesphere There are two problems with your interpretation. (1) The radius of the event horizon depends on the frame of reference. As you fall into the black hole, you would see the event horizon shrinking in front of you, so in your falling frame you never cross it until you hit the singularity. (2) You speak of the event horizon as of some place, such as "plane" or "surface". This is incorrect. A surface is a space-like object. However, the event horizon is a ligh-tlike object. So it is not a surface in space that you could cross, but more like a set of worldliness of beams of light.
May 1, 2018 at 10:09 history edited Qmechanic
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May 1, 2018 at 10:08 history duplicates list edited John Rennie duplicates list edited from Does a diatomic molecule falling into a black hole dissociate? to Does a diatomic molecule falling into a black hole dissociate?, Taking selfies while falling, would you be able to notice a horizon before hitting a singularity?
May 1, 2018 at 9:39 comment added John Rennie See also Taking selfies while falling, would you be able to notice a horizon before hitting a singularity?
May 1, 2018 at 9:38 comment added John Rennie See the question I've linked. It's true that light can't move outwards at or inside the event horizon, but because you're falling inwards you catch up with the light being emitted outwards. So even inside the black hole light appears to be travelling normally.
May 1, 2018 at 9:37 history closed John Rennie black-holes Duplicate of Does a diatomic molecule falling into a black hole dissociate?
May 1, 2018 at 9:36 comment added toriningen Also, to clarify, I'm specifically asking about supermassive black holes, so the curvature of the event horizon and tidal forces are both negligible enough.
May 1, 2018 at 9:28 history asked toriningen CC BY-SA 3.0