Timeline for Transformation of $d^4x$ under translation disregarded?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 4, 2018 at 10:01 | comment | added | image357 | @SRS: you have to change you integral bounds! This will compensate for $\phi(x-a)$. | |
| Apr 28, 2018 at 8:04 | comment | added | Arnaldo Maccarone | You are right, I believe that it is only a matter of sloppy notation. | |
| Apr 28, 2018 at 6:55 | review | Low quality answers | |||
| Apr 28, 2018 at 9:01 | |||||
| Apr 28, 2018 at 6:43 | comment | added | SRS | I know that. That's what is used in arriving at step (3) from step (2). But the step (1) looks like $\phi(x)$ is mapped to $\phi^\prime(x-a)$ and $x$ to $x$. I'm suspicious whether it is $d^4x$ or $d^4x^\prime$ in step (1). Although it will not matter in the end. | |
| Apr 28, 2018 at 6:38 | history | answered | Arnaldo Maccarone | CC BY-SA 3.0 |