Timeline for Energy lost in capacitors
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 4, 2018 at 21:49 | answer | added | Ján Lalinský | timeline score: 0 | |
| Nov 4, 2018 at 20:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 30, 2018 at 14:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| S Apr 16, 2018 at 9:58 | history | suggested | Dave Coffman | CC BY-SA 3.0 |
cleaned up formatting
|
| Apr 16, 2018 at 8:53 | answer | added | Farcher | timeline score: 2 | |
| Apr 16, 2018 at 5:07 | comment | added | niels nielsen | it is not lost, it is stored in the polarization of the dielectric slab by the electric field which exists across it. | |
| Apr 16, 2018 at 5:03 | comment | added | user192755 | Nope I meant lost only. | |
| Apr 16, 2018 at 4:47 | answer | added | Archisman Panigrahi | timeline score: 0 | |
| Apr 16, 2018 at 4:45 | review | Suggested edits | |||
| S Apr 16, 2018 at 9:58 | |||||
| Apr 16, 2018 at 4:32 | comment | added | The Photon | Why would you assume V is constant while charging? That's like assuming the speed of a car doesn't change when the car accelerates. | |
| Apr 16, 2018 at 4:30 | comment | added | Steeven | When you say "lost", I guess you mean "stored", right? | |
| Apr 16, 2018 at 4:25 | review | First posts | |||
| Apr 16, 2018 at 4:45 | |||||
| Apr 16, 2018 at 4:22 | history | asked | user192755 | CC BY-SA 3.0 |